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9-0.25x^2=0
a = -0.25; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-0.25)·9
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3}{2*-0.25}=\frac{-3}{-0.5} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3}{2*-0.25}=\frac{3}{-0.5} =-6 $
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